Math Help: Figuring out average damage each round.

DM Magic

Adventurer
I'm working on some math for an RPG I'm putting together and I am hoping for a little assistance. Here's the scenario:

There are three characters. One is wielding a weapon that does d6 damage, one a weapon that does d8, and the final a weapon that does d10. Assuming they hit the monster they are fighting 60% of the time, what is the average damage output each round?
 

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Well, start off with figuring out your average damage assuming you hit every round: 1d6 = 3.5, 1d8 = 4.5, and 1d10 = 5.5.

Now multiply each by .6, and we get: d6 = 2.1, d8 = 2.25, and d10 = 3.3. Rounding down, that means the d6 and d8 weapons are doing an average of 2 points of damage each round and the d10 weapon's doing slightly better at 3 points of damage each round.

Johnathan
 

Well, start off with figuring out your average damage assuming you hit every round: 1d6 = 3.5, 1d8 = 4.5, and 1d10 = 5.5.

Now multiply each by .6, and we get: d6 = 2.1, d8 = 2.25, and d10 = 3.3. Rounding down, that means the d6 and d8 weapons are doing an average of 2 points of damage each round and the d10 weapon's doing slightly better at 3 points of damage each round.

Johnathan
Snap, I didn't know it was that easy! Thanks!
 

I'm working on some math for an RPG I'm putting together and I am hoping for a little assistance. Here's the scenario:

There are three characters. One is wielding a weapon that does d6 damage, one a weapon that does d8, and the final a weapon that does d10. Assuming they hit the monster they are fighting 60% of the time, what is the average damage output each round?
Hit % * average per die.
For 1dX, the average is (X/2)+0.5. For more dice, add the averages.

So..
0.6×3.5 = 1.8 + 0.3 = 2.1
0.6×4.5 = 2.4 + 0.3 = 2.7
0.6×5.5 = 3 + 0.3 = 3.3
 

Hit % * average per die.
For 1dX, the average is (X/2)+0.5. For more dice, add the averages.

So..
0.6×3.5 = 1.8 + 0.3 = 2.1
0.6×4.5 = 2.4 + 0.3 = 2.7
0.6×5.5 = 3 + 0.3 = 3.3

What are the middle sections for?

For example, I know that 0.6 × 3.5 = 2.1, but what's the 1.8 + 0.3 for?
 

Whoops - math error on my part with the d8 - aramis erak is correct, it's 2.7, not my original 2.25. (I'm not sure what I did there to get to where I did.).

And in his examples, in each case he did the multiplication of .6 times the number before the decimal and then .6 times the .5 separately, then added them together.

Johnathan
 

What are the middle sections for?

For example, I know that 0.6 × 3.5 = 2.1, but what's the 1.8 + 0.3 for?
showing the math in progress. Long multiplication, sans calculator, using polynomial method (and thus distributive and commutative properties of multiplication). given digits A, B, C, D
(A.B) * (C.D) is the same as
(A.B * C.0)+(A.B * 0.D) and
(A.0 × C.0)+(A.0 × 0.D) + (0.B × C.0) + (0.B × 0.D)
 

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